Find the sum or difference

Find the sum or difference.

(a^2-4a+6) + (-3a^2+13a+1)

(9w^3-11w^2+2w) - (-6w^2-3w+11)

Please show how you did it! Thanks!

(a^2-4a+6) + (-3a^2+13a+1)
First you combine the terms equations into one
a^2 - 3a^2 - 4a + 13a + 6 + 1
Then you simplify
-2a^2 + 9a + 7


(9w^3-11w^2+2w) - (-6w^2-3w+11)
this one is a little bit different

the second equation is going to be reversed since there is a minus sign in front of it. the minus is the same as a -1, so you will use the distributive property
(9w^3-11w^2+2w) - (-6w^2-3w+11) will become
9w^3-11w^2+2w + 6w^2 + 3w - 11
then combine like terms
9w^3 - 11w^2 + 6w^2 + 2w + 3w - 11
9w^3 - 5w^2 + 5w - 11

hope i helped

First eliminate the parenthesis... when the sign before is -, then change all signs inside.

1) a^2 -4a + 6 -3a^2 + 13a + 1... now add the similar terms... it is -2a^2 +9a + 7 OK!


2) 9w^3 - 11w^2 + 2w + 6w^2 +3w - 11 now add the similar terms... it is 9w^3 -5w^2 + 5w -11 OK!