How to solve: -4tan(2x-12)+2 = 6

I know I need to get the tangent factor by itself; I need to subtract 2 from both sides, and divide -4 on both sides.

I get: tan(2x-12) = -1

Now what do I do from here?

tan(a-b) = (tan a - tan b) / 1 + tan(a)*tan(b)

rewrite as
4tan(12-2x)+2=6

subtract by 2 and divide boty sides by 4

tan(12-2x) = 1

take the arctan of both sides

12-2x = arctan(1)
arctan(1) = PI/4

12 - 2x = PI/4

subtract 12 from both sidex
-2x = PI/4 - 12 or simplified and factored -2x = 1/4 (PI - 48)

divide both sides by -2

X = 1/8 * (48 - PI) the 48 and PI switch because of the division of a negative

2x-12 = 3pi/4 + k*pi where k is any integer
x-6 = 3pi/8 + k*pi/2
x = 3pi/8+k*pi/2+6