A GAMMA photon has a wavelength of 5.00 x 10^-13 m. What is the energy of the photon in electron volts?
I attempted this problem by using the equation E = (hc) / lambda and got 2480000 eV, but this was incorrect. Any ideas? Does it matter that this is a gamma photon?
I attempted this problem by using the equation E = (hc) / lambda and got 2480000 eV, but this was incorrect. Any ideas? Does it matter that this is a gamma photon?
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E = hc/λ = 3.975^-13 J
1eV = 1.60^-19 J
E = 3.975^-13 J / 1.60^-19 J .. .. ►E = 2.48^6 eV .. looks like I agree with you !
(is a more exact answer required ..2,484,400 eV ?)
1eV = 1.60^-19 J
E = 3.975^-13 J / 1.60^-19 J .. .. ►E = 2.48^6 eV .. looks like I agree with you !
(is a more exact answer required ..2,484,400 eV ?)
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When L = c/F we have E = hF = hc/L = 6.626E-34*299E6/5E-13 = 3.96235E-13 Joules. Now look it up in the Unit Converter [See source.] 2473083 eV. ANS.
Looks to me you might have chopped off some decimal points where you shouldn't have. But as you're close, I have to think you worked it correctly. And no...a photon is a photon...no matter what its energy level might be.
Looks to me you might have chopped off some decimal points where you shouldn't have. But as you're close, I have to think you worked it correctly. And no...a photon is a photon...no matter what its energy level might be.