Please solve exactly for x:
81^(5-2x)=(1/9)^(2x-3)
81^(5-2x)=(1/9)^(2x-3)
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81^(5 - 2x) = (1/9)^(2x - 3)
9^2(5 - 2x) = 9^[-(2x - 3)]
2(5 - 2x) = -(2x - 3)
10 - 4x = -2x + 3
-2x = -7
x = 7/2
9^2(5 - 2x) = 9^[-(2x - 3)]
2(5 - 2x) = -(2x - 3)
10 - 4x = -2x + 3
-2x = -7
x = 7/2
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OK funny symbol.
Put everything in terms of base 9.
9^2(5x-2) = 9^-(2x-3).
Now equate exponents
10x-4 = -2x+3
12x = 7
x = 7/12.
Put everything in terms of base 9.
9^2(5x-2) = 9^-(2x-3).
Now equate exponents
10x-4 = -2x+3
12x = 7
x = 7/12.