And how do i write a balanced equation for it?
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In this case, Mg metal will displace Al ions, because Mg is more reactive. See the reactivity series
http://en.wikipedia.org/wiki/Reactivity_…
3Mg + 2Al(3+) -----> 3Mg(2+) + 2Al
You need the coefficients to balance the charge on both sides of the equation.
http://en.wikipedia.org/wiki/Reactivity_…
3Mg + 2Al(3+) -----> 3Mg(2+) + 2Al
You need the coefficients to balance the charge on both sides of the equation.
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The observation is as follows, a dull grey precipitate is formed due to displacement of Al by Mg.
Mg is higher than Al in the activity series so, Al gets reduced by Mg.
The REDOX reaction is as follows:
3Mg + 2Al3+ ----------> 3Mg2+ + 2Al
(the electrons of mg are transferred to Al)
Mg is higher than Al in the activity series so, Al gets reduced by Mg.
The REDOX reaction is as follows:
3Mg + 2Al3+ ----------> 3Mg2+ + 2Al
(the electrons of mg are transferred to Al)
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are all the products in a solid state or would the 2Al be a liquid please?