log[e](x+10)=4
log'e'(x+10)=4 (the 'e' is on bottom)
Please show full working out
answer = 44.59 (please correct me if answer is incorrect)
log'e'(x+10)=4 (the 'e' is on bottom)
Please show full working out
answer = 44.59 (please correct me if answer is incorrect)
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log(base e) = ln.
ln(x + 10) = 4
take antilogs
x + 10 = e^4
x = e^4 - 10 = 54.598 - 10 = 44.598
ln(x + 10) = 4
take antilogs
x + 10 = e^4
x = e^4 - 10 = 54.598 - 10 = 44.598
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log to the base e is usually written as ln
here ln(x+10)=4 0r e^4=x+10 x=e^4-10 but e is a constant having the value 2.718....
three decimals will do so e^4=54.4544 54.4544-10=44.4544
here ln(x+10)=4 0r e^4=x+10 x=e^4-10 but e is a constant having the value 2.718....
three decimals will do so e^4=54.4544 54.4544-10=44.4544
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log[e](x+10)=4
ln(x+10)=4
x+10=e^4
x=e^4-10
x=54.60-10
x=44.60
ln(x+10)=4
x+10=e^4
x=e^4-10
x=54.60-10
x=44.60
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The log(e) which equals 4
is 54 .598..............using inv of ln
so
x + 10 = 54.598
x = 44 .598
is 54 .598..............using inv of ln
so
x + 10 = 54.598
x = 44 .598