Values of SIN and COS question just one?

I don't know how to figure this out the question is:

- For each of the following angles, t, determine the values of SIN t and COS t:

(a) t=0

(b) t= 3pi over 2

How do i figure them out please answer, thankyou

(a) sin0 = 0 and cos0 = 1

(b) sin(3π/2) = -sin(π/2) = -1 and cos(3π/2) = -cos(π/2) = 0

:)>

sint = sin0 = 0 & cost = cos0 =1 [ when t= 0 ]
sin3pi/2= sin(pi/2 + pi) = cospi = - 1
cos 3pi/2= cos( pi+ pi/2) = - cospi/2 =0

sin 0 = 0
cos 0=0
sin 3pi/2=( square root of 3) /2
cos 3pi/2=- 1/2