Can I get detailed steps on how to complete this please? Thank you very much!
-
−1 ≤ sin x ≤ 1
0 ≤ sin²x ≤ 1
As x approaches infinity, sin²x fluctuates between 0 and 1 (it does not approach 1 as stated above), while (x²+1) approaches infinity, so 1/(x²+1) approaches 0
0 * some number between 0 and 1 = 0
So limit = 0
0 ≤ sin²x ≤ 1
As x approaches infinity, sin²x fluctuates between 0 and 1 (it does not approach 1 as stated above), while (x²+1) approaches infinity, so 1/(x²+1) approaches 0
0 * some number between 0 and 1 = 0
So limit = 0
-
note that sinx oscilates between -1 and 1.
As it approaches infinity, its value will be 1.
1 / x^2 + 1
Bottom goes to infinity.
so it will be 0
As it approaches infinity, its value will be 1.
1 / x^2 + 1
Bottom goes to infinity.
so it will be 0