Considere the family of curves defined by f(x)=csquareroot x, where c is constant. Let the function m(h) be defined as the slope of the secant line that passes through the function f(x) over the closed interval (bracket 9,9+h bracket)
Question: Using an analytic tecnique calculate lim m(h). Show all Steps
2) How would you graph the function m(h) for c=-6 and c=12? What function would i need to graph?
HELPP! i've been spending the last like 2 hours trying to figure it out
Question: Using an analytic tecnique calculate lim m(h). Show all Steps
2) How would you graph the function m(h) for c=-6 and c=12? What function would i need to graph?
HELPP! i've been spending the last like 2 hours trying to figure it out
-
Lim m(h) = [f(9+h)-f(9)]/[9+h-9]
Lim m(h) =c*[sqrt(9+h)-sqrt(9)]/[h]
Lim m(h) =c*[sqrt(9+h)-3]/h
Use L hopitals rule here or use binomial approximation to calculate,
Lim m(h) =c*[1/2*sqrt(9+h)]/1
Lim m(h) =1/2*1/sqrt9
Lim m(h) =1/6
2) to graph y=-6*sqrt(x) or 12*sqrt(x)
we need to see the graph of sqrt(x) first,
put graph of square root of x in google search and u see the graph and notice it.
to draw 12*sqrtx
just draw enlarged version of it.
wheb drawing -6sqrtx u need to shift graph below x axis and then enlarge it or u can see it using nticing the graph of -sqrtx
Hope it helps :)
Lim m(h) =c*[sqrt(9+h)-sqrt(9)]/[h]
Lim m(h) =c*[sqrt(9+h)-3]/h
Use L hopitals rule here or use binomial approximation to calculate,
Lim m(h) =c*[1/2*sqrt(9+h)]/1
Lim m(h) =1/2*1/sqrt9
Lim m(h) =1/6
2) to graph y=-6*sqrt(x) or 12*sqrt(x)
we need to see the graph of sqrt(x) first,
put graph of square root of x in google search and u see the graph and notice it.
to draw 12*sqrtx
just draw enlarged version of it.
wheb drawing -6sqrtx u need to shift graph below x axis and then enlarge it or u can see it using nticing the graph of -sqrtx
Hope it helps :)