Help finding the solution for sinx - 2 = cosx - 2

I'm at sinx - cosx = 0 and I have no idea what to do from here .. please help.

sinx - 2 = cosx - 2
sin(x) = cos(x)
tan(x) = 1
x = pi/4 + n(pi) radians where n is an integer
OR
x = 45 + 180n degrees where n is an integer

at sinx=cosx i squared both sides got sinx^2=cosx^2 then subtract get cosx^2-sinx^2=0 cosx^2-sinx^2 is the same as cos2x so cos2x=0 then get rid of cos by taking the cos^-1 so 2x=90 and 2x=270 that is in degrees or 2x=pi/2 and 2x=(3pi)/2 in radians then depending on what your answer is supposed to be in you get x equals 45 degrees=n(360) and 135 degrees + n(360) or you get x equals pi/4+(2pi) and x equals 3pi/4+n(2pi)

sinx-2=cosx-2
We can add 2 to both members of the equation.
sinx=cosx
tgx=1
x=π/4+kπ where k is a relative integer.

sinx -->cosx ie sinx/cosx --->1 tanx --->1 x--->45deg