How would you write 5logx + 3logy - 2log(z-5) as a single log

[From: ] [author: ] [Date: 12-08-02] [Hit: ]

5logx + 3logy -2 log(z-5) [n.b.: log (ab) = log a + log b ; log (a/b) = log a - log b]
= log((x^5y^3)/(z-5)^2) (answer)

log[(x^5y^3)/(z - 5)^2]

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