Molarity question help

How many grams of na2co3 are contained in 80ml of a 1.50 M solution?

The 12.72 g answer shown from other replies is correct. I just wanted to sure that a real easy way to solve for GRAMS of solute need to prepare a specific volume of a known molarity is:

g = Liters x Molarity X molar mass of solute

applied here....

g = 0.08L X 1.50 M x 106 g/mole = 12.7 g

Molarity = (mass of solute / MW of solute) / L of solution

1.50 moles/L = (mass of Na2CO3 / 84 g/mol) / (80/1000) ===> solve for mass Na2CO3

mass of Na2CO3 = 10 grams ===> answer

moles= molarity x L
moles Na2CO3= 1.50 x 0.08
moles Na2CO3= 0.12

g Na2CO3= 0.12 moles x 106 g/mole
g Na2CO3= 12.7