write the exponential function as an equivalent logarithmic equation
1. 8+2e^x=58
2. 9^2x=5
take the log or ln of both side. simplify using the power rule
3. 7^x+1=3
4. 5^x+2=6^x-7
thank youu!
1. 8+2e^x=58
2. 9^2x=5
take the log or ln of both side. simplify using the power rule
3. 7^x+1=3
4. 5^x+2=6^x-7
thank youu!
-
I am a little confused about if parenthesis are missing in some of these problems. In equation #2, for example, I grouped the "2x." In equation #3, I worked it two ways. The 2nd way is how it was originally presented.
1. 8 + 2eˣ = 58
2eˣ = 58 - 8
eˣ = 25
x = ln(25), or x = 2ln(5)
2. 9⁽²ˣ⁾ = 5
2xln(9) = ln(5)
x = ln(5)/(2ln(9)), or x = ln(5)/(4ln(3))
3. 7⁽ˣ⁺¹⁾ = 3
(x+1) = ln(3)/ln(7)
x = ln(3)/ln(7) - 1
7ˣ + 1 = 3
7ˣ = 2
x = ln(2)/ln(7)
4. 5ˣ + 2 = 6ˣ - 7
x ≈ 1.90951
1. 8 + 2eˣ = 58
2eˣ = 58 - 8
eˣ = 25
x = ln(25), or x = 2ln(5)
2. 9⁽²ˣ⁾ = 5
2xln(9) = ln(5)
x = ln(5)/(2ln(9)), or x = ln(5)/(4ln(3))
3. 7⁽ˣ⁺¹⁾ = 3
(x+1) = ln(3)/ln(7)
x = ln(3)/ln(7) - 1
7ˣ + 1 = 3
7ˣ = 2
x = ln(2)/ln(7)
4. 5ˣ + 2 = 6ˣ - 7
x ≈ 1.90951
-
1. 2e^x=50, x=ln25.
2. 2xln9=ln5, x=ln5/(2ln9).
3. 7^x=2, x=ln2/ln7. Or if you meant 7^(x+1)=3, then (x+1)ln7=ln3 and x=ln3/ln7 -1.
4. 6^x - 5^x =9. This can't be simplified any further. Perhaps you meant 5^(x+2)=6^(x-7)? If so
x=(7ln6 - 2ln5)/(ln6 -ln6).
2. 2xln9=ln5, x=ln5/(2ln9).
3. 7^x=2, x=ln2/ln7. Or if you meant 7^(x+1)=3, then (x+1)ln7=ln3 and x=ln3/ln7 -1.
4. 6^x - 5^x =9. This can't be simplified any further. Perhaps you meant 5^(x+2)=6^(x-7)? If so
x=(7ln6 - 2ln5)/(ln6 -ln6).