Help on my math problem

use quadratic formula.

3n^2=-8n-3

3n^2 + 8n + 3

x = (-8 +/- sqrt(64 - 4(3)(3)) / 2(3)

x = (-8 +/- sqrt(64 - 36)) / 6

x = (-8 +/- sqrt(28)) / 6

x = (-8 +/- sqrt(4) * sqrt(7)) / 6

x = (-8 +/- 2 sqrt(7)) / 6

x = (4 +/- sqrt(7)) / 3

Solve that and you have your answer.

I hope this information was very helpful.

3n^2+8n+3 = 0
n = [-8±sqrt(64-36)]/6
n = [-8±sqrt(28)]/6
n = [-4±sqrt(7)]/3