4x-y=8 and y-int=-3
PLEASE HELP! I don't get it :(
PLEASE HELP! I don't get it :(
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The formula of any straight line is y=mx+c, so rearrange the equation into the form y=mx+c where m is the gradient and c is the y-intercept
4x-y=8
4x-8=y
y=4x-8
two lines are perpendicular when the product of their gradients is -1. The gradient of the given line is 4, so;
4X?=-1 (4 multiplied by something gives negative 1)
4X(-1/4)=-1 (4 quarters give 1, so four negative quarters give -1)
So the gradient of the perpendicular is -1/4 and the y-intercept is -3 (as given in question)
Substitute into the form y=mx+c
y=-1/4x-3
4x-y=8
4x-8=y
y=4x-8
two lines are perpendicular when the product of their gradients is -1. The gradient of the given line is 4, so;
4X?=-1 (4 multiplied by something gives negative 1)
4X(-1/4)=-1 (4 quarters give 1, so four negative quarters give -1)
So the gradient of the perpendicular is -1/4 and the y-intercept is -3 (as given in question)
Substitute into the form y=mx+c
y=-1/4x-3