Im not sure how far civilization would have gotten, some recent researches even suggest arithmetic came before language as we know it.-youd spend your entire life not knowing how many parents, sibling
Ive already done the first two that were similar, but only through trial and error. Ive attempted this next one, but its never right!
Create a set of at least five data points such that the standard
Im assuming that you want to evaluate the following integral:
2 ∫ (dy / dx)(d²y / dx²) dx
Note that dy/dx = y (x) and d²y / dx² = y(x) :
2 ∫ y(x) y(x) dx
Now make a substitution:
u = y(x)
du = y
Solve this i dont really need the steps just the answer. √5-3√5-2√20the √ is a square root--4√ 5-2√20 can be rewritten as 4√5
√5 - 3√5 - 4√5
√5 - 7√5 = -6√5--6√5
For all x (greater then or equal to) 0 and y (greater then or equal to)
√(250x^9y^4)= ?
Thank you and show work please!! :-)-factor out perfect squares and take their square roots
√(250 x^9 y^4) =
√
Use synthetic division to divide the following problems. Show your work for full credit. You may use the synthetic division template to show your work.
(x2 + 13x + 40) ÷ (x + 8) (1 point)
(2x2 – 23x
(1+x)^2(-1)+(1-x)(2)(1+x)
thanks-Hello
You have only (1+x) as common factor,
(1+x)[(1+x)(-1)+(1-x)(2)] = (1+x)[-1-x+2-2x] = (1+x)(1-3x)
Hope it helped
Bye !-(1+x)^2(-1)+(1-x)(2)(1+x)
= (1+x)[(1+x
Okay. So here is the problem :
The sum of the digits of a two-digit number is 14. If the digits are reversed, the number is increased by 18. What is the number?
Please help me solve the problem usin
Two concentric circles have radii R and r, where R>r.
R increases at a constant rate of 1 cm per minute and the area between the two circles remains constant at 25cm square. At the instant when R =
thanks :D
Do I need to make it into the general form to get -b/2a?-No, you can read it right from the vertex equation if you realize that since x is the squared term, the line of symmetry will be a v
1) the formula for length of the hypotenuse of a triangle (short sides p and q) is r^2 = p^2 + q^2.
a) Making p the subject of the formula:
My answer: r^2 = p^2 + q^2 (p) = r^2 - q^2 = p^2 =final ans
sin(x+18)=cos(x-8)
Umm i keep getting wrong answer, answer is 40.
This is my working out, please point out my error and correct it.
T=theta
sin(x+18)=sin(90-T)
T=(x-8)
sin(x+18)=90-x-8)= sin(82-x)