Assume the radius of the earth to be 3960 miles. Three positions on the surface of the earth are defined by: i) Latitude= O degrees, longitude= 60 degrees ii) Latitude= 90 degrees, Longitude= 60 degrees. iii) latitude= 0 degrees, longitude= 90 degrees. My teacher gave me these hints. 1.) Draw a diagram of a sphere 2.) The coordinates form a right triangle 3.) Use proportions 4.) Use the circumference formula. I would really appreciate your help. Thank you so much.
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Here is another hint: two points are on the equator and one point is the north pole, so it is an isosceles triangle with two right angles.
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Latitude is theta and longitude is phi of polar coordinate
point 1: x = 0, y = 0 and z = R cos o = R
Point 2: (R*sin 90*cos 60, R*sin 90* sin 60, 0)
Point 3: ( 0, 0, R)
side 12 = sq rt[(R/2)^2 + +(R*sq rt(3)/2)^2 + R ^2] = R* sq rt(2)
side 23 = sq rt[(R/2)^2 + +(R*sq rt(3)/2)^2 + R ^2] = R *sq rt(2)
side 31 : sq rt(R^2) = R
Perimeter [2*sq rt(2)+1]*R = 15161 mile
point 1: x = 0, y = 0 and z = R cos o = R
Point 2: (R*sin 90*cos 60, R*sin 90* sin 60, 0)
Point 3: ( 0, 0, R)
side 12 = sq rt[(R/2)^2 + +(R*sq rt(3)/2)^2 + R ^2] = R* sq rt(2)
side 23 = sq rt[(R/2)^2 + +(R*sq rt(3)/2)^2 + R ^2] = R *sq rt(2)
side 31 : sq rt(R^2) = R
Perimeter [2*sq rt(2)+1]*R = 15161 mile