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# Please help show all steps

[From: ] [author: ] [Date: 11-04-23] [Hit: ]
34 - 28.26 = 226.28.26 / 226.08 = 0.Probability of bullseye = 9PI/81PI = 9/81 = 1/9 = 0.......
Essay; show all work. A simple dartboard has three areas… the main board has a radius of 9 inches, there is a circle with a radius of 5 inches, and the bullseye has a radius of 3 inches. What is the probability of a random dart landing inside the bullseye? Round to the nearest thousandth.

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the middle board is a distraction

find the area of the outer board

pi(9)^2 = 254.34

pi(3)^2 = 28.26

the bullseye is inside the main board so to find the probability you have to find the area of JUST the main board

254.34 - 28.26 = 226.08

now divide to find the probability

28.26 / 226.08 = 0.125 or 1/8

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Area of the circle = PI (9)^2 = 81PI
Area of circle with radius 3 = PI (3)^2 = 9PI

Probability of bullseye = 9PI/81PI = 9/81 = 1/9 = 0.1111
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