Three coins are tossed. Find the probability that no more than one coin lands heads up.

There are 3 ways where only 1 head will show: htt, tht, tth and there is 1 way where no heads will show: ttt. There are 3 ways where 2 heads will show: hht, thh, hth and finally, there is 1 way where only heads wil show: hhh).
So, there are 4 ways out of 8 that no more than 1 head shows. The probability is 4/8 = 1/2 = 50%.
So, there are 4 ways out of 8 that no more than 1 head shows. The probability is 4/8 = 1/2 = 50%.

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