The answer is supposed to be in y=mx+b form.
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2y > -10 - 5x
y > -5 - 5/2 x
y > -(5/2) x - 5
The solution is the area that lies above the line y = -(5/2)x - 5, which is a line with a y-intercept of -5, and a slope of -5/2
y > -5 - 5/2 x
y > -(5/2) x - 5
The solution is the area that lies above the line y = -(5/2)x - 5, which is a line with a y-intercept of -5, and a slope of -5/2
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Yes ∃ someone such that ∀ function inequality problems such as 5x+2y>-10 they can find and graph the solution. I can prove this to you, I am that someone.
Lol, I'm just messing with you--I'm a math major and the way you worded this question, gramatically and logically, you're just asking if there is someone out there that can solve the problem, and of course there is. Btw, in advanced math speak, ∃=there exists, ∀=for all.
Anyway, here's my solution:
5x + 2y > -10
2y > -5x - 10
y > -2.5x - 5
To graph that, just draw a dashed line starting at (0,-5), with a slope of -2.5, and then shade in everything above it.
Lol, I'm just messing with you--I'm a math major and the way you worded this question, gramatically and logically, you're just asking if there is someone out there that can solve the problem, and of course there is. Btw, in advanced math speak, ∃=there exists, ∀=for all.
Anyway, here's my solution:
5x + 2y > -10
2y > -5x - 10
y > -2.5x - 5
To graph that, just draw a dashed line starting at (0,-5), with a slope of -2.5, and then shade in everything above it.
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you cant get an inequality to turn into an equation and even if you meant to put it on a GRID then you need 2 equations
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5x + 2y > -10
2y > -5x - 10
y > (-5/2)x - 5
I don't really get what you're asking but that is how you solve for y
2y > -5x - 10
y > (-5/2)x - 5
I don't really get what you're asking but that is how you solve for y
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5x+2y>-10
2y>-5x-10
y>-5x/2-5
2y>-5x-10
y>-5x/2-5