A 200-N sphere 0.20 m in radius rolls without slipping 6.0 m down a ramp that is inclined at 40° with the horizontal. What is the angular speed of the sphere at the bottom of the slope if it starts from rest?answer in rad/s
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I = k*m*r²; for a solid sphere, k = 2/5:
Drop height = L*sinΘ = 6sin40° = 3.857 m
v = √[2gh/(1+k)] = 7.348 m/s
w = v/r = 36.74 rad/sec
Drop height = L*sinΘ = 6sin40° = 3.857 m
v = √[2gh/(1+k)] = 7.348 m/s
w = v/r = 36.74 rad/sec