Find the height from which the rock was launched.
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# Find the height from which the rock was launched.

[From: ] [author: ] [Date: 11-09-23] [Hit: ]
-Use the value= 9.810for the free-fall acceleration.-If you actually mean the range to be 9 meters,h = 5.62 m-It travels a horizontal distance of = 9.time = 9 / [7* cos 30] = 1.......
A rock thrown with speed 7.00m/s and launch angle 30.0 (above the horizontal) travels a horizontal distance of = 9.00m/s before hitting the ground. From what height was the rock thrown?

-Use the value = 9.810 for the free-fall acceleration.

-
If you actually mean the range to be 9 meters, the launch height

h = 5.62 m

-
It travels a horizontal distance of = 9.00m

time = 9 / [7* cos 30] = 1.48s

vertical motion
s = ut + 0.5 * at^2
s = 7 * sin 30 * 1.48 - 0.5 * 9.81 * 1.48^2

s = -5.56 m

the rock was thrown from a height of 5.56m -answer

note: negative sign denotes distance opposite 7m/s.
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