A rock thrown with speed 7.00m/s and launch angle 30.0 (above the horizontal) travels a horizontal distance of = 9.00m/s before hitting the ground. From what height was the rock thrown?
-Use the value = 9.810 for the free-fall acceleration.
-Use the value = 9.810 for the free-fall acceleration.
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If you actually mean the range to be 9 meters, the launch height
h = 5.62 m
h = 5.62 m
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It travels a horizontal distance of = 9.00m
time = 9 / [7* cos 30] = 1.48s
vertical motion
s = ut + 0.5 * at^2
s = 7 * sin 30 * 1.48 - 0.5 * 9.81 * 1.48^2
s = -5.56 m
the rock was thrown from a height of 5.56m -answer
note: negative sign denotes distance opposite 7m/s.
time = 9 / [7* cos 30] = 1.48s
vertical motion
s = ut + 0.5 * at^2
s = 7 * sin 30 * 1.48 - 0.5 * 9.81 * 1.48^2
s = -5.56 m
the rock was thrown from a height of 5.56m -answer
note: negative sign denotes distance opposite 7m/s.