What is the net force required for a 1.5 X 105 kg train car to move from 20 km/h to 60 km/h over 100 meters?
a. 9.3 X 104 N
b. 1.8 X 105 N
c. 4.4 X 105 N
d. 9.3 X 105 N
e. 4.5 X 106 N
a. 9.3 X 104 N
b. 1.8 X 105 N
c. 4.4 X 105 N
d. 9.3 X 105 N
e. 4.5 X 106 N
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We will need to use F = ma to find F. We have m, but not a. However, we have all the information we need to find a. Note that values for v are converted to m/s.
Use:
Vf^2 = Vo^2 + 2ax
(16.68)^2 = (5.56)^2 + 2a(100)
277.78 = 30.86+ 200a
a = 1.24 m/s^2
Now use this value for a in F = ma:
F = ma
F = (1.5 * 10^5)(1.24)
=180,000 N or 1.8 * 10^5
Use:
Vf^2 = Vo^2 + 2ax
(16.68)^2 = (5.56)^2 + 2a(100)
277.78 = 30.86+ 200a
a = 1.24 m/s^2
Now use this value for a in F = ma:
F = ma
F = (1.5 * 10^5)(1.24)
=180,000 N or 1.8 * 10^5