could someone please help me with this math problem.
A certain "Burger Joint" advertises that a customer can have his or her hamburger with or without any or all of the following: catsup, mustard, mayonnaise, lettuce ,tomato, onion, pickle, cheese, or mushrooms. How many different kinds of hamburger orders are possible?
could you also explain to me how you got the answer also
Ive tried 8! and p(8,8) both answers look impossible.
thank you for your time
A certain "Burger Joint" advertises that a customer can have his or her hamburger with or without any or all of the following: catsup, mustard, mayonnaise, lettuce ,tomato, onion, pickle, cheese, or mushrooms. How many different kinds of hamburger orders are possible?
could you also explain to me how you got the answer also
Ive tried 8! and p(8,8) both answers look impossible.
thank you for your time
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so for each condiment, you can have two options: "add" or "don't add", so the answer is
2^N where N is the number of condiments, which is 9.
So we can have 2^9 = 2 * 2 * 2 * ... * 2 (9times) = 512.
2^N where N is the number of condiments, which is 9.
So we can have 2^9 = 2 * 2 * 2 * ... * 2 (9times) = 512.