How do I evaluate the integral
From -1 to 2, the integral
1/x^2 dx
From -1 to 2, the integral
1/x^2 dx
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This is the same as the integral of x^(-2) dx.
The integral of x^n dx is x^(n+1)/(n+1) for any n except -1.
The integral of x^n dx is x^(n+1)/(n+1) for any n except -1.