"Note the expression: y=x^(1/2). If x doubles, what happens to y?"
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"Note the expression: y=x^(1/2). If x doubles, what happens to y?"

[From: ] [author: ] [Date: 11-09-22] [Hit: ]
so it doesnt matter what happens to the x value, but the y value is always the sqaure root of the x value.-You can try and punch in numbers to see what you get.If x = 2 then y = .........
Please explain your reasoning

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Look carefully at this equation. what does x^1/2 equal? Its the square root of x! so for any value at x^1/2, y will always = the square root of the x value. for instance

4^1/2 = 2 (note that 4 is a perfect square)

now take
8^1/2 = 2.8284

so it doesnt matter what happens to the x value, but the y value is always the sqaure root of the x value.

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You can try and punch in numbers to see what you get. If x = 2 then y = ..... If x = 4 then y = .... Or you could substitute in a new variable in for x. Say y = (2 * x) ^(1/2) Then you have to remember your multiplications rules. Is 2^(1/2) * x^(1/2) equal to (2*x)^(1/2)? You can always plug in numbers for x if you are having problems.

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y is multiplied by 2^(1/2).

(xz)^(1/2) = x^(1/2) times z^(1/2).

if z=2, then (2x)^(1/2) = x^(1/2) times 2^(1/2).

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Y would be multiplied by 1/2 cause you would need to take the reciprocal.

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it trips over Z and falls off the alphabet...Reason: its xlumsy
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