Work-Energy Theorem (physics help)
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Work-Energy Theorem (physics help)

[From: ] [author: ] [Date: 11-09-22] [Hit: ]
thanks!*-a) when reaches the maximum height, the speed is zero,KE (initial) - KE (max. height) = (0.5* 0.......
A 200-g ball thrown vertically up with an initial speed of 20 m/s reaches a maximum height of 18 m.

(a) the change in its kinetic energy
(b) the work done by gravity
(c) are the two quantities just calculated equal?

*No need to fully work out the problem as I can, would just like help setting up formulas, thanks!*

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a) when reaches the maximum height, the speed is zero, so the change of kinetic energy is

KE (initial) - KE (max. height) = (0.5* 0.2 * 20^2) - (0.5* 0.2 *0^2) = I am sure you can calculate this

b) the work done by gravity is : m*g*h = 0.2*9.8*18 = you can calculate this

c) just compare the result above
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