Help solving this differential equation

x`(t) +3t^2 x(t) = 3t^2

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The equation above is the same as the equation

dy/dx+3x^2 * y=3x^2

Subtract 3x^2 * y from both sides to get

dy/dx=3x^2 - 3x^2 * y

factor out 3x^2

dy/dx= 3x^2(1-y)

Now use separation of variables to get

dy/(1-y) = 3x^2 dx

Integrating both sides gives

-ln(1-y)=x^3+C

So ln(1-y)= -x^3+C

which gives 1-y=C e^(-x^3)

Hence y= 1 - Ce e^(-x^3)

where e is the exponential e=2.718...