How to find the x intercepts of y= -x(x+2)^2 +16
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How to find the x intercepts of y= -x(x+2)^2 +16

[From: ] [author: ] [Date: 11-09-21] [Hit: ]
......
10 points, thanks.

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When y = 0,
0 = -x(x+2)^2 +16
x(x+2)² − 16 = 0
x(x²+4x+4) − 16 = 0
x³ + 4x² + 4x − 16 = 0
x = 1.39.

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/the easiest way is too graph it and where the line crosses the x axis each time are the x intercepts
1
keywords: intercepts,to,the,How,16,find,of,How to find the x intercepts of y= -x(x+2)^2 +16
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