I've been at the equation for awhile and I'm having trouble figuring it out. Help is greatly appreciated.
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6x - (2x+3) ≥ 4x - 5
6x - 2x - 3 ≥ 4x - 5
4x - 3 ≥ 4x - 5
as the x's cancel out and it is true that -3 is bigger than or equal to -5 it doesnt matter what value x is it will always be true.
So the answer is x is all real values.
6x - 2x - 3 ≥ 4x - 5
4x - 3 ≥ 4x - 5
as the x's cancel out and it is true that -3 is bigger than or equal to -5 it doesnt matter what value x is it will always be true.
So the answer is x is all real values.
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1. Order of operations: Parenthesis first + Distributive property --> 6x - 2x - 3 ≥ 4x - 5
2. Simplify the left side --> 4x -3 ≥ 4x - 5
3. Subtract both sides by 4x --> -3 ≥ -5
4. That means you can plug in any real numbers for x to make the inequality true.
Therefore, "x equals to all real numbers" is the solution.
2. Simplify the left side --> 4x -3 ≥ 4x - 5
3. Subtract both sides by 4x --> -3 ≥ -5
4. That means you can plug in any real numbers for x to make the inequality true.
Therefore, "x equals to all real numbers" is the solution.
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6x - (2x + 3) ≥ 4x - 5
6x - 2x - 3 ≥ 4x - 5
0 ≥ - 8
Answer: 0 ≥ - 8
6x - 2x - 3 ≥ 4x - 5
0 ≥ - 8
Answer: 0 ≥ - 8
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4x - 3 ≥ 4x - 5
No unique solution.
No unique solution.
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reduces to -3>=-5 or some other true statement depending on what legal steps you do means it true for any value of x