How do you solve 6x-(2x+3)≥4x-5
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How do you solve 6x-(2x+3)≥4x-5

[From: ] [author: ] [Date: 11-09-21] [Hit: ]
3.4. That means you can plug in any real numbers for x to make the inequality true. Therefore, x equals to all real numbers is the solution.No unique solution.......
I've been at the equation for awhile and I'm having trouble figuring it out. Help is greatly appreciated.

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6x - (2x+3) ≥ 4x - 5

6x - 2x - 3 ≥ 4x - 5

4x - 3 ≥ 4x - 5

as the x's cancel out and it is true that -3 is bigger than or equal to -5 it doesnt matter what value x is it will always be true.

So the answer is x is all real values.

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1. Order of operations: Parenthesis first + Distributive property --> 6x - 2x - 3 ≥ 4x - 5
2. Simplify the left side --> 4x -3 ≥ 4x - 5
3. Subtract both sides by 4x --> -3 ≥ -5
4. That means you can plug in any real numbers for x to make the inequality true.
Therefore, "x equals to all real numbers" is the solution.

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6x - (2x + 3) ≥ 4x - 5
6x - 2x - 3 ≥ 4x - 5
0 ≥ - 8

Answer: 0 ≥ - 8

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4x - 3 ≥ 4x - 5

No unique solution.

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reduces to -3>=-5 or some other true statement depending on what legal steps you do means it true for any value of x
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