Write an equation of the line containing the given point and parallel to the given line

(7,-8) 8x-3y=5

slope of given line 8x -3y = 5 is 8/3 so slope of required line is -3/8, and the equation of line passing through (7, -8) having slope -3/8 is
(y+8) = (-3/8)(x-7) or]
8y + 64 = -3x +21 or 3x + 8y + 43 = 0