start, how long will it take jeff to catch up with roger? They will each have to run___of a mile?
Please, someone help me
Please, someone help me
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at time = 1 minute
distance for roger = 1/9 of a mile
distance for jeff = 0
at time = 2 minutes
distance for roger = 2/9 of a mile
distance for jeff = 1/6 of a mile
at time = 3 minutes
distance for roger = 3/9 of a mile
distance for jeff = 2/6 of a mile
They have both run 1/3 of a mile at 3 minutes.
distance for roger = 1/9 of a mile
distance for jeff = 0
at time = 2 minutes
distance for roger = 2/9 of a mile
distance for jeff = 1/6 of a mile
at time = 3 minutes
distance for roger = 3/9 of a mile
distance for jeff = 2/6 of a mile
They have both run 1/3 of a mile at 3 minutes.