Magnitude of baseball mitt physics
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Magnitude of baseball mitt physics

[From: ] [author: ] [Date: 11-09-21] [Hit: ]
What was the magnitude of the average force applied by the ball on the glove?d=distance = 0.0=32^2 +2*a*0.the force applied to stop the baseball is F = m a = 0.......
A 0.150-kg baseball traveling 32.0 m/s strikes the catcher's mitt, which, in bringing the ball to rest, recoils backward 15.0 cm.

What was the magnitude of the average force applied by the ball on the glove?

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first we find the acceleration from

vf^2=v0^2 + 2ad

vf=final vel =0
v0 = initial vel = 32 m/s
a=accel
d=distance = 0.15m

0=32^2 +2*a*0.15 => a= = 3413m/s/s

the force applied to stop the baseball is F = m a = 0.15kg*a = - 512N

the ball exerts the same force in the opposite direction on the glove
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