A 0.150-kg baseball traveling 32.0 m/s strikes the catcher's mitt, which, in bringing the ball to rest, recoils backward 15.0 cm.
What was the magnitude of the average force applied by the ball on the glove?
What was the magnitude of the average force applied by the ball on the glove?
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first we find the acceleration from
vf^2=v0^2 + 2ad
vf=final vel =0
v0 = initial vel = 32 m/s
a=accel
d=distance = 0.15m
0=32^2 +2*a*0.15 => a= = 3413m/s/s
the force applied to stop the baseball is F = m a = 0.15kg*a = - 512N
the ball exerts the same force in the opposite direction on the glove
vf^2=v0^2 + 2ad
vf=final vel =0
v0 = initial vel = 32 m/s
a=accel
d=distance = 0.15m
0=32^2 +2*a*0.15 => a= = 3413m/s/s
the force applied to stop the baseball is F = m a = 0.15kg*a = - 512N
the ball exerts the same force in the opposite direction on the glove