A researcher observes hydrogen emitting photons of energy 2.86 eV.

What are the quantum numbers of the two states involved in the transition that emits these photons?
Thanks in anticipation =)

Energy emission of hydrogen atom for different quantum state transitions are as under:
The formula for energy emission is
E = 13.6 (1/m^2 - 1/n^2), n > m
m = 1, n = 2 => E = 10.2 eV
m = 2, n = 3 => E = 1.89 eV
m = 2, n = 4 => E = 2.55 eV
m = 2, n = 5 => E = 2.86 eV
=> answer is Quantum states 2 and 5. Transition from state 5 to 2.