Two Dimensional Problem help
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Two Dimensional Problem help

[From: ] [author: ] [Date: 11-09-20] [Hit: ]
Im using the displacement formula, but I really have no idea where to go from there or if Im even going in the right direction. I drew a right a right triangle with vectors connecting to each other to help me solve this problem, but to no avail.If anyone can send me in the right direction with steps on how to solve a problem like this that would be great. (If solving with integrals can be avoiding please do,......
a) A box falls out of an airplane that is traveling horizontally at 100m/s. The plane is at an altitude of 300m. Where does the box land relative to where it was dropped from?

I don't know whether I'm going in the right direction or not. I put the Velocity as 100 m/s and the height as 300m.

I'm using the displacement formula, but I really have no idea where to go from there or if I'm even going in the right direction. I drew a right a right triangle with vectors connecting to each other to help me solve this problem, but to no avail.

If anyone can send me in the right direction with steps on how to solve a problem like this that would be great. (If solving with integrals can be avoiding please do, because in class we were taught not to use any calculus)

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Key point: the vertical motion is free fall, the horizontal motion remains at uniform speed of 100 m/s (because there is no force in the horizontal direction if we neglect air resistance.)

The time of free fall can be calculated first:

h = 1/2 g t^2 => t = sqrt(2 h /g) = sqrt(2 * 300 m / 9.81 s) = 7.82 seconds.

In that time, the horizontal displacement will be

s = v_horizontal * t = 100 m/s * 7.82 s = 782 m.
So the box will land 782 m further than the point it was dropped from (and 300 m lower of course)
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