How many GRAMS of bromine are present in 2.12E+21 molecules of carbon tetrabromide ?
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carbon tetrabromide --> CBr4 --> 4 atoms bromine per molecule
if 2.12E+21 molecules --> 8.48E+21 atoms of bromine
8.48E+21 atoms --> 0.0141 moles of bromine
0.0141 moles Br * 79.9 g Br per mole --> 1.13 g Br
if 2.12E+21 molecules --> 8.48E+21 atoms of bromine
8.48E+21 atoms --> 0.0141 moles of bromine
0.0141 moles Br * 79.9 g Br per mole --> 1.13 g Br
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Molar mass (molecular weight) of CBr4 is 331.6g , this many grams has 6.02E23 molecules CBr4
2.12E21 molecules* 331.6g/6.02E23molecules =1.168g CBr4
2.12E21 molecules* 331.6g/6.02E23molecules =1.168g CBr4