What is the IUPAC name of this hydrocarbon:

CH3(CH3)CHCHCHCH3

1,methyl pent2-ene

you numbering from the side nearer to double bond then you can do it easy

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4-methylpent-2-ene.

Am assuming your molecule looks like this:

..H...H.......H..H
HC--C--C=C--CH
..H...]...H.......H
....HCH
......H

Longest chain = 5 PENT
double bond = ENE
Substituent = METHYL
Double bond on C#2, since you have to # by LOWEST possible. This makes it -2-ene.
Since #2 is double bone, methyl is on #4 of 5, hence 4-METHYL.
Put it all together, you get:
4-methylpent-2-ene.

Easy.

the IUPAC bame of this hydrocarbon is but-2-ene or 2-butene
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Hope this helps!! =)