The pH of a 1 L solution containing 100 mL of 1M acetic acid and 4.1g of sodium acetate (formula weight 82g/mol; pK=4.76) is...
a) 2.76
b) 3.76
c) 4.76
d) 5.76
e) 6.76
Please show the full solution...
a) 2.76
b) 3.76
c) 4.76
d) 5.76
e) 6.76
Please show the full solution...
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Use Henderson Hasselbach Equation
pH = pKa + log [base]/[acid]
[base]=(4.1/82)/0.100L = 0.5
pH = 4.76 + log (0.5)/1
pH = 4.46
pH = pKa + log [base]/[acid]
[base]=(4.1/82)/0.100L = 0.5
pH = 4.76 + log (0.5)/1
pH = 4.46