Math problem helppppppppppppp

solve for x

1= (1/(x^2+2x) + (x-1)/x)

The right-hand side:
1 / (x² + 2x) + (x - 1) / x = 1/[x(x + 2)] + (x - 1) / x
= [1 + (x + 2).( x - 1)] / [x(x + 2)],
and that equals 1, on the LHS.

So, 1 + (x + 2).( x - 1) = x(x + 2),
i.e.: 1 + (x² + x - 2) = x² + 2x,
i.e.: x² + x - 1 = x² + 2x,
i.e.: x - 1 = 2x,
so: x = - 1
 
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1 = (1/(x^2+2x) + (x-1)/x)
1 = (1/(x^2+2x) + (x-1)(x+2)/((x+2)x))
1 = (1/(x^2+2x) + (x^2+x-2)/(x^2+2x))
1 = (x^2+x-1)/(x^2+2x)
x^2 + 2x = x^2 + x - 1
2x = x - 1
x = -1