Factor completely Remember to look first for a common factor. Check by multiplying. If a polynomial is prime, state this. I PROMISE IF YOU EXPLAIN EVERY STEP TO ME ABOUT HOW TO DO THIS PROBLEM I WILL RANK YOU THE HIGHEST I CAN AND i WILL REMEMBER YOUR NAME TO KEEP RANKING YOU THE BEST, PLEASE DO IT ASAP PLEASE!!!
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Okie dokie. Here we have a polynomial in the form ax^2 + bx + c with:
a = 1
b = -1
c = 1
To see if it even has real solutions, you first find what is called the discriminant.
The discriminant is equal to b^2 - 4ac. If it is negative there are no real solutions and the polynomial will be prime.
The discriminant in your case is equal to:
(-1)^2 - (4*1*1)
This equals -3. The polynomial is prime.
a = 1
b = -1
c = 1
To see if it even has real solutions, you first find what is called the discriminant.
The discriminant is equal to b^2 - 4ac. If it is negative there are no real solutions and the polynomial will be prime.
The discriminant in your case is equal to:
(-1)^2 - (4*1*1)
This equals -3. The polynomial is prime.
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My comment is I need those other two ASAP:(
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