Keeping in mind that there are more than black and red on the board... I'm working on a strategy. Who want in? lol
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There are 18 red, 18 black, and 2 green on a roulette wheel.
So the probability of a non-black is 20/38 = 10/19
It seems you are asking: If the roulette wheel is spun 9 times, what is the probability that none of the spins will be black?
That would be (10/19)^9 = .003099, or just a bit over 3 chances in a thousand.
So the probability of a non-black is 20/38 = 10/19
It seems you are asking: If the roulette wheel is spun 9 times, what is the probability that none of the spins will be black?
That would be (10/19)^9 = .003099, or just a bit over 3 chances in a thousand.
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There is French and American Roulette. Let's assume that we are talking about American Roulette.
Then there are two special pockets : 0 and 00. So we have 38 pockets in American Roulette, 18 black ones among them. So the odds that Black is not landed on is 20/38. The odds for that to happen 9 consecutive times are (20/38)^9 = 0.00309897.
Then there are two special pockets : 0 and 00. So we have 38 pockets in American Roulette, 18 black ones among them. So the odds that Black is not landed on is 20/38. The odds for that to happen 9 consecutive times are (20/38)^9 = 0.00309897.