Can someone please explain this problem step by step to me.
Please and Thank You!
Please and Thank You!
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Average is the sum of numbers divided by the number count.
(3 + x)/2 = 5
3 + x = 10
x = 7
(5 + y)/2 = 7
5 + y = 14
y = 9
Average of x & y =
(x + y)/2 =
(7 + 9)/2= 8
(3 + x)/2 = 5
3 + x = 10
x = 7
(5 + y)/2 = 7
5 + y = 14
y = 9
Average of x & y =
(x + y)/2 =
(7 + 9)/2= 8
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Normally you have to distinguish between "mean," "median" and "mode" when you talk "average." For this problem, let's go with "mean." The mean value for a number between 3 and 7 is 5. You can get there by rephrasing the question: What number added to 3 divided by 2 equals 5? So X = 5.
The same technique works for 5 + 9 / 2 = 7.
X = 7 and y = 9. Together they add up to 16. Divide that by 2 and you get 8. So the answer to your problem is 8. Hope this helps!!
The same technique works for 5 + 9 / 2 = 7.
X = 7 and y = 9. Together they add up to 16. Divide that by 2 and you get 8. So the answer to your problem is 8. Hope this helps!!
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The average of a and b is (a+b)/2
So what we have is (3+x)/2 = 5 and (5+y)/2=7. We need to figure out what x and y are, then calculate their average.
Figuring out x: (3+x)/2 = 5
Multiply both sides by 2: 3+x = 10
Subtract 3 from both sides: x = 7
Figuring out y: (5+y)/2 = 7
Multiply both sides by 2: 5+y=14
Subtract 5 from both sides: y=9
The average of 7 and 9 = (7+9)/2 = 16/2=8
So what we have is (3+x)/2 = 5 and (5+y)/2=7. We need to figure out what x and y are, then calculate their average.
Figuring out x: (3+x)/2 = 5
Multiply both sides by 2: 3+x = 10
Subtract 3 from both sides: x = 7
Figuring out y: (5+y)/2 = 7
Multiply both sides by 2: 5+y=14
Subtract 5 from both sides: y=9
The average of 7 and 9 = (7+9)/2 = 16/2=8
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The average of two numbers is their sum divided by 2, so...
(3 + x) / 2 = 5
Multiply both sides by 2:
3 + x = 10
Subtract 3 from both sides.
x = 7
Now to find y:
(5 + y) / 2 = 7
Multiply both sides by 2:
5 + y = 14
And subtract 5 from both sides:
y = 9
So now we know that x = 7 and y = 9. The average of x and y is therefore:
(7 + 9) / 2
16 / 2
8
I hope that helps. Good luck!
(3 + x) / 2 = 5
Multiply both sides by 2:
3 + x = 10
Subtract 3 from both sides.
x = 7
Now to find y:
(5 + y) / 2 = 7
Multiply both sides by 2:
5 + y = 14
And subtract 5 from both sides:
y = 9
So now we know that x = 7 and y = 9. The average of x and y is therefore:
(7 + 9) / 2
16 / 2
8
I hope that helps. Good luck!
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When taking the average (or mean) of only two numbers, the average will be the middle of the two numbers. So 5 has to be half way between 3 and x. x must be 7. Similarly, 7 must be half way between 5 and y. y must be 9. The average of 7 and 9 is 8.
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"The average of 3 and x is 5,"
(3 + x)/2 = 5
3 + x = 10
x = 7
"the average of 5 and y is 7"
(5 + y)/2 = 7
5 + y = 14
y = 9
"what is the average of x and y"
(7 + 9)/2 = 8
(3 + x)/2 = 5
3 + x = 10
x = 7
"the average of 5 and y is 7"
(5 + y)/2 = 7
5 + y = 14
y = 9
"what is the average of x and y"
(7 + 9)/2 = 8
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(3 + x)/2 = 5,, solve for x which is 7
(5 + y)/2 = 7, solve for y which is 9
average of x and y = (x + y )/2... plug in x=7, y=9
(7+9) / 2 = 8
(5 + y)/2 = 7, solve for y which is 9
average of x and y = (x + y )/2... plug in x=7, y=9
(7+9) / 2 = 8
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3+x=10
5+y=14 ...Add equations
8+x+y = 24
x+y = 16
(x+y)/2 = 8
Average = 8
5+y=14 ...Add equations
8+x+y = 24
x+y = 16
(x+y)/2 = 8
Average = 8