Had a problem on my Cal test today that asked me to give a possible graph that would satisfy several limits.
f(0)=0, f(x)=4 as x approaches infinity, and f(x)=negative infinity as x approaches negative infinity.
I placed a point at (0,0) and drew a curve to the right that approached y=4 and ran off the graph. Then a straight line from (0,0) to the left with a -1 slope that ran off the graph.
Does that seem correct? Thoughts?
f(0)=0, f(x)=4 as x approaches infinity, and f(x)=negative infinity as x approaches negative infinity.
I placed a point at (0,0) and drew a curve to the right that approached y=4 and ran off the graph. Then a straight line from (0,0) to the left with a -1 slope that ran off the graph.
Does that seem correct? Thoughts?
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That sounds fine to me. If they didn't give you an equation, the graph you made would satisfy the conditions. You mean a +1 slope of course, down and to the left?