Can somebody please help me with physics? step by step would be great
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Can somebody please help me with physics? step by step would be great

[From: ] [author: ] [Date: 11-09-16] [Hit: ]
......
An object is thrown downward with an initial
speed of 3 m/s from a height of 59 m above
the ground. At the same instant, a second
object is propelled vertically up from ground
level with a speed of 36 m/s .
At what height above the ground will the
two objects pass each other? The acceleration
of gravity is 9.8 m/s
2
.
Answer in units of m

-
write the equations of motion for the two objects

y1(t)=59+3t-1/2gt^2

y2(t)=36t-1/2gt^2

set y1=y2:

59+3t - 1/2 gt^2 = 36 t -1/2gt^2

59=33t => t=59/33s

substitute this time into either y(t) equation to find the height of the objects at this time
1
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