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Need help with physics problem!

[From: ] [author: ] [Date: 11-09-15] [Hit: ]
0 . It runs at constant speed for 69.3and slows down at a rate of 3.49until it stops at the next station.Find the total distance covered.-as it takes 14 seconds to accelerate at 1.......
Been trying to solve this problem for the loooooongest time. Any help would be REALLY REALLY appreciated. THANKS!

A subway train starts from rest at a station and accelerates at a rate of 1.60 for 14.0 . It runs at constant speed for 69.3 and slows down at a rate of 3.49 until it stops at the next station. Find the total distance covered.

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as it takes 14 seconds to accelerate at 1.60 m/s^2
it must take 14 * 1.6 /3.49 = 6.42 secs to slow down again.

Now what speed did it reach?
v = at = 1.6 * 14 = 22.4 m/s

During acceleration and deceleration the AVERAGE speed is 1/2 max speed = 11.2 m/s

So to get the total distance we have distance = sum ( speed * time)
= 11.2 * 14 + 22.4 * 69.3 + 11.2 * 6.42
= 1.78 Km
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