Can you help me about age problem

So here's the question.

Eddie is three times as old as Dave, seven years ago, Eddie was five times as old as Dave.
How old are they?

Let
x=Eddie’s current age
y=Dave’s current age
Eddie is three times as old Dave means
x=3y…………..(1)
Seven years ago means we have to subtract 7 from both ages
x-7=y-7
then
Eddie was five times old as Dave
x-7=5(y-7)
x-7=5y-35
x=5y-35+7
x=5y-28…………(2)



Put the value of x from (1) to (2)
x=5y-28
3y=5y-28
3y-5y=-28
-2y=-28
Divide by -2 both sides of above equation
-2y/-2=-28/-2
y=14
Put the value of y in equation (1)
x=3y
x=3(14)
x=42
Eddie is 42 and Dave is 14 years old.

Georgia I just moved from Florida to France

PERSON......................PRESENT.AG… 7)
**************************************…
Eddie.................................…

Dave..................................…

Eddie = 5 times Dave

3x-7=5(x-7)

3x-7=5x-37..........Subtract 3x from both sides

-7=2x-37...............Add 37 to both sides

30 = 2x

x=15

Dave is 15
Eddie is 3(15) =45

Let the age of Dave be x.
then age of Eddie is 3x(at present),
seven years ago,eddie was 5 times as old as dave.
=> (3x-7)=5(x-7)
3x-7=5x-35
=>2x=28 and x=14
=>age of eddie is 42 and that of dave is 14

dave age = x
eddies age = 3x
seven yrs ago
daves age = x- 7
eddies age = 3x -7
3x - 7 = 5 (x-7)
3x - 7 = 5 x- 35
5x-3x =35-7
2x = 28
x= 14
eddie= 42 yrs old
dave = 14 yrs

E = 3D
E -- 7 = 5(D -- 7)
3D -- 7 = 5D -- 35
OR 2D = 28 OR D = 14 then E = 3D = 3*14 = 42
David 14 yrs, Eddie 42 yrs Answer.

eddie: 15
Dave: 13