Help in mathematics, urgent. . .

If 5+3+2 = 151012,
9+2+4= 183662, 8+6+3 =
482466, 5+4+5= 202504 then
what will be the answerof 7+2+5?
Only 2% people are able to
solvethis aptitude question

It's 143542
The key is,
let the given numbers be a, b and c respectively
the first and second digit of the answer is a x b
the third and fourth digit is a x c
the last two digits is from b x (a + b) then flipping the answer around.

7 x 2 = 14
7 x 5 = 35
7 + 5 = 12
12 x 2 = 24
flip it around, and you get 42

Answer is 143542. How?? Here is the Solution:

Let the question in a+b+c
1) 1st two digits is a product of a & b.
2) Next two digits is a product of a & c.
3) And the last two digit is the reverse of b(a+c)....

5+3+2 = 151012
9+2+4 = 183662
8+6+3 = 482466
5+4+5 = 202504
7+2+5=

5+3+2 = (15)(10)(12)
9+2+4 = (18)(36)(62)
8+6+3 = (48)(24)(66)
5+4+5 = (20)(25)(04)
7+2+5=

5+3+2 = (5*3)(5*2)(12) (5+2)*3=7*3=21 => 12
9+2+4 = (9*2)(9*4)(62) (9+4)*2=13*2=26 => 62
8+6+3 = (8*6)(8*3)(66) (8+3)*6=11*6=66 => 66
5+4+5 = (5*4)(5*5)(04) (5+5)*4=10*4=40 => 04
7+2+5= (7*2)(7*5)(42) (7+5)*2=12*2=24 => 42

7+2+5= 143542

7 + 2 + 5 = 143542
Explanation: a + b+ c leads to a six digit number!