Completing the square to find the turning point

Y= -9/8 (x^2 - 12x + 20)

Help please....

Reena, the question says to complete the square to find the turning point; you did neither of those things.

y = -9/8 (x^2 - 12x + 20)
= -9/8 (x^2 - 12x + 36 - 16)
= -9/8 (x - 6)² - 9/8 (-16)
= -9/8 (x - 6)² + 18
So the turning point is at (6, 18).

Y= -9/8 (x^2 - 12x + 20)

Y= -9/8 [(x^2 - 12x +__)] + (-9/8)[20] - (-9/8)(__)

............(1/2)(-12)=-6.....(-6)^2=3…

Y= -9/8 [(x^2 - 12x +_36_)] + (-9/8)[20] - (-9/8)(_36_)

Y=(-9/8)(x-6)^2+(-45/2)+(81/2)

Y=(-9/8)(x-6)^2+36/2

Y=(-9/8)(x-6)^2+18

Vertex..................(6,18)

Y= -9/8 (x^2 - 12x + 20)
Y= -9/8 (x^2 - 10x -2x + 20)
Y= -9/8 (x - 10) (x -2)