2x ^2=18x-36
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2x^2=18x-36
2x^2-18x+36 (move the right side stuff over)
Then (2*36) which = 72. You have to find the 2 #'s that multiply to get 72 and that add to -18
choices [minus negatives] (1*72, 2*36, 3*24, 4*18, 6*12, 8*9)
So the only choice is 6*12 or in this case -6+-12 (which = -18)
So...
2x^2-6x-12x+36
(2x^2-6x)(-12x+36)
2x(x-3)-12(x-3)
Set both equal to "0"
(2x-12)=0; (x-3)=0
2x=12.........x=3
x=6
x=6, 3 or x=6 x=3
2x^2-18x+36 (move the right side stuff over)
Then (2*36) which = 72. You have to find the 2 #'s that multiply to get 72 and that add to -18
choices [minus negatives] (1*72, 2*36, 3*24, 4*18, 6*12, 8*9)
So the only choice is 6*12 or in this case -6+-12 (which = -18)
So...
2x^2-6x-12x+36
(2x^2-6x)(-12x+36)
2x(x-3)-12(x-3)
Set both equal to "0"
(2x-12)=0; (x-3)=0
2x=12.........x=3
x=6
x=6, 3 or x=6 x=3