When the pressure is applied
A. C(s) + O2(g) <-> CO2(g)
B. CaCO3(s) <-> CaO(s) + CO2(g)
C. 2Mg(s) + O2(g) <-> 2MgO(s)
D. 2H2(g) + O2(g) <-> 2H2O(g)
A. C(s) + O2(g) <-> CO2(g)
B. CaCO3(s) <-> CaO(s) + CO2(g)
C. 2Mg(s) + O2(g) <-> 2MgO(s)
D. 2H2(g) + O2(g) <-> 2H2O(g)
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According to le Chataliers principle increase in P must result in decrease of V . In case of gases V is proportional to moles.
Only in case 'B' there are no gases on L.H.S. and 1 gas on R.H.S. so it moves towards reactants. In all other cases no. of gases molecules are greater/ equal in reactants
Only in case 'B' there are no gases on L.H.S. and 1 gas on R.H.S. so it moves towards reactants. In all other cases no. of gases molecules are greater/ equal in reactants
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B, as when pressure is increased the point of equilibrium moves towards the side with the lower number of gas molecules in order to reduce the pressure back towards normal